.14x^2-2=5

Solution for .14x^2-2=5 equation:

.14x^2-2=5

We move all terms to the left:

.14x^2-2-(5)=0

We add all the numbers together, and all the variables

.14x^2-7=0

a = .14; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·.14·(-7)
Δ = 3.92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{3.92}}{2*.14}=\frac{0-\sqrt{3.92}}{0.28}
=-\frac{\sqrt{}}{0.28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{3.92}}{2*.14}=\frac{0+\sqrt{3.92}}{0.28}
=\frac{\sqrt{}}{0.28}
$